![]() |
Atomic Physics |
The number of protons in an atom (nucleus) is given by the Z of the nucleus. We have
Element | Number of Protons in Nucleus, Z |
hydrogen |
1 |
helium |
2 |
lithium |
3 |
berylium |
4 |
and so on |
So, how do the neutrons fit into this scheme? Whether an atom contains zero neutrons or many neutrons in its nucleus does not affect the type of element it is; it is the number of protons which determines the chemical element. The neutrons do affect the mass of the atom (its atomic weight, A). To set the jargon, consider hydrogen with Z = 1 (1 proton).
All of the above are isotopes of hydrogen.
The mass of a proton is ~1,836 times that of an electron while neutrons and protons have roughly the same mass ===> the mass of an atom is contained in its nucleus while the nucleus is only
If we make an analogy with the Solar System, we can imagine that the nucleus is the Sun, and the electrons are the planets. The electrical force plays the role of gravity. This analogy is useful, however, there are important differences between how our Solar System works and how an atom works.
The above properties of atoms are not intuitive and it wasn't until the twentieth century when they were reasonably well-understood and could be modeled. The physics used to model these and other related phenomena is referred to as Quantum Mechanics. We will have more to say about Quantum Mechanics in the future. For now consider the following representation for the structure of an atom:
where n is the level. The lowest level is n = 1, the next higher level is n = 2, and so on.
Because the strength of the electrical force depends upon the charge of the nucleus (number of protons) and the number of electrons, different atoms have different energy structures.
Note that the largest transitions (longest arrows) require the highest energy photons, particles of light, because the transitions have the largest changes in energy. The photons which produce the largest transitions therefore involve the photons with the shortest wavelengths (since E = hc/W = hf).
Comment: (i) A neutral atom is denoted by I. An atom which has lost 1 electron is denoted by II. An atom which has lost 2 electrons is denoted by III, and so on. For example, neutral hydrogen is HI; singly ionized hydrogen is HII.
Comment: (ii) To ionize an atom, all we require is that the photon have enough energy to lift the electron out of the well. If the photon has more than this threshold energy, it simply gives the excess energy to the electron (as kinetic energy). So, in terms of the appearance of the spectrum, we find that there is a threshold where ionization begins followed by a broad trough which extends to shorter wavelengths (higher energies). Such ionization edges are seen in the spectra of many stars.
Lyman lines fall in the ultraviolet. Balmer lines fall in the optical. Paschen, Brackett, and Pfund lines fall in the infrared.